IPMAT 2020 Question Paper IPM Indore Quantitative Ability. Solve questions from IPMAT 2020 Question Paper from IPM Indore and check the solutions to get adequate practice. The best way to ace IPMAT is by solving IPMAT Question Paper. To solve other IPMAT Sample papers, go here: **IPM Sample Paper**

Question 6 : Ashok purchased pens and pencils in the ratio 2: 3 during his first visit and paid Rs. 86 to the shopkeeper. During his second visit, he purchased pens and pencils in the ratio 4: 1 and paid Rs. I 12 . The cost of a pen as well as a pencil in rupees is a positive integer. If Ashok purchased four pens during his second visit, then the amount he paid in rupees for the pens during the second visit is __________.

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Ratio of pen : pencil is 2:3 and he spends Rs 86

Next time The ratio of pen and pencil is 4:1 and he spends Rs 112

Second time Ashok purchased 4 pens, So the ratio of Pen and Pencil is 4:1

Hence he purchased 4 pens and 1 pencil during his second visit

Let price of pen be 'x' and price of pencil be 'y'

Then,

4x + y = 112. -----(2)

2x + 3y = 86 -----(1)----(From first visit)

(1) Is in Ratios, so it can be 4x + 6y = 86 (or)

6x + 9y = 86 (or)

8x + 12y = 86

Since, From (2), 4 pen and a pencil costs Rs 112

4 pens and 6 pencils has too cost more than 112 (Given that Cost of a pen and pencil is a positive integer)

In that case 4x + 6y = 86 (or)

6x + 9y = 86 (or)

8x + 12y = 86

These possibilities are ruled out

Only possibility is 2x + 3y = 86

Solving (1) and (2) by Elimination Method

We get y = 12 ---> Cost of a pen

On second visit, he pays a total of Rs 112, One pencil and 4 pen.

1 Pencil costs Rs 12, 112 - 12 = Rs 100

He paid Rs 100 during his second visit for the pens.

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